std::reverse_copy
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header <algorithm>
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|   template< class BidirIt, class OutputIt > OutputIt reverse_copy( BidirIt first, BidirIt last, OutputIt d_first );  | 
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Copies the elements from the range [first, last), to another range beginning at d_first in such a way, that the elements in the new range are in reverse order. 
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[edit] Parameters
| first, last | - | the range of elements to copy | 
| d_first | - | the beginning of the destination range | 
| Type requirements | ||
 -BidirIt must meet the requirements of BidirectionalIterator.
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 -OutputIt must meet the requirements of OutputIterator.
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[edit] Return value
Output iterator to the element past the last element copied.
[edit] Possible implementation
template<class BidirIt, class OutputIt> OutputIt reverse_copy(BidirIt first, BidirIt last, OutputIt d_first) { while (first != last) { *(d_first++) = *(--last); } return d_first; }  | 
[edit] Example
#include <vector> #include <iostream> #include <algorithm> int main() { std::vector<int> v({1,2,3}); std::for_each(std::begin(v), std::end(v), [&](int value){ std::cout << value << " "; }); std::cout << std::endl; std::vector<int> destiny(3); std::reverse_copy(std::begin(v), std::end(v), std::begin(destiny)); std::for_each(std::begin(destiny), std::end(destiny), [&](int value){ std::cout << value << " "; }); std::cout << std::endl; }
Output:
1 2 3 3 2 1
[edit] Complexity
linear in the distance between first and last
[edit] See also
|    reverses the order elements in a range   (function template)  | |