C++ program that uses dynamic programming algorithm to solve the optimal binary search tree problem

#include<iostream>
#include<conio.h>
#include<stdio.h>
using namespace std;
#define MAX 10
int find(int i,int j);
void print(int,int);
int p[MAX],q[MAX],w[10][10],c[10][10],r[10][10],i,j,k,n,m;
char idnt[7][10];
 
main()
{
	cout << "enter the no, of identifiers";
	cin >>n;
	cout <<"enter identifiers";
	for(i=1;i<=n;i++)
	gets(idnt[i]);
	cout <<"enter success propability for identifiers";
	for(i=1;i<=n;i++)
		cin >>p[i];
	cout << "enter failure propability for identifiers";
	for(i=0;i<=n;i++)
		cin >> q[i];
	for(i=0;i<=n;i++)
	{
		w[i][i]=q[i];
		c[i][i]=r[i][i]=0;
		w[i][i+1]=q[i]+q[i+1]+p[i+1];
		r[i][i+1]=i+1;
		c[i][i+1]=q[i]+q[i+1]+p[i+1];
	}
	w[n][n]=q[n];
	r[n][n]=c[n][n]=0;
	for(m=2;m<=n;m++)
	{
		for(i=0;i<=n-m;i++)
		{
		     j=i+m;
		     w[i][j]=w[i][j-1]+p[j]+q[j];
		     k=find(i,j);
		     r[i][j]=k;
		     c[i][j]=w[i][j]+c[i][k-1]+c[k][j];
		}
	}
       cout <<"\n";
       print(0,n); }
 
int find(int i,int j)
{
int min=2000,m,l;
for(m=i+1;m<=j;m++)
if(c[i][m-1]+c[m][j]<min)
{
min=c[i][m-1]+c[m][j];
l=m;
}
return l;
}
void print(int i,int j)
{
if(i<j)
puts(idnt[r[i][j]]);
else
return;
print(i,r[i][j]-1);
print(r[i][j],j);
}