std::rotate_copy
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                    | Defined in header  <algorithm> | ||
| template< class ForwardIt, class OutputIt > OutputIt rotate_copy( ForwardIt first, ForwardIt n_first, | ||
Copies the elements from the range [first, last), to another range beginning at d_first in such a way, that the element n_first becomes the first element of the new range and n_first - 1 becomes the last element. 
| Contents | 
[edit] Parameters
| first, last | - | the range of elements to copy | 
| n_first | - | an iterator to an element in [first, last)that should appear at the beginning of the new range | 
| d_first | - | beginning of the destination range | 
| Type requirements | ||
| - ForwardItmust meet the requirements ofForwardIterator. | ||
| - OutputItmust meet the requirements ofOutputIterator. | ||
[edit] Return value
Output iterator to the element past the last element copied.
[edit] Possible implementation
[edit] Example
#include <algorithm> #include <vector> #include <iostream> int main() { std::vector<int> src = {1, 2, 3, 4, 5}; auto pivot = std::find(src.begin(), src.end(), 3); std::vector<int> dest(src.size()); std::rotate_copy(src.begin(), pivot, src.end(), dest.begin()); for (const auto &i : dest) { std::cout << i << ' '; } std::cout << '\n'; }
Output:
3 4 5 1 2
[edit] Complexity
linear in the distance between first and last
[edit] See also
| rotates the order of elements in a range (function template) | |

