Leap Year checker : If « Language Basics « Python

Home
Python
1.2D
2.Application
3.Buildin Function
4.Class
5.Data Structure
6.Data Type
7.Database
8.Development
9.Dictionary
10.Event
11.Exception
12.File
13.Function
14.GUI Pmw
15.GUI Tk
16.Language Basics
17.List
18.Math
19.Network
20.String
21.System
22.Thread
23.Tuple
24.Utility
25.XML
Python » Language Basics » If 




Leap Year checker
Leap Year checker



import sys
import string
def julian_leap(y=2000):
    if (y%4== 0:
        return 1
    return 0
def gregorian_leap(y=2000):
    if (y%400== 0:
         return 1
    elif (y%100== 0:
         return 0
    elif (y%4== 0:
         return 1
    return 0

 years = [1999,2000,2001,1900]
 print julian_leap()
 print gregorian_leap()
 if julian_leap():
     print "Julian 2000 yes"
 if gregorian_leap():
     print "Gregorian 2000 yes"
 for x in years:
     if julian_leap(x):
         print "Julian", x, "is leap"
     else:
         print "Julian", x, "is not leap"
     if gregorian_leap(x):
         print "Gregorian", x, "is leap"
     else:
         print "Gregorian", x, "is not leap"
           
       














Related examples in the same category
1.Nested if statementNested if statement
2.if-else structureif-else structure
3.if-elif-else structureif-elif-else structure
4.if structureif structure
5.if Statements: if, elif and elseif Statements: if, elif and else
6.Boolean operation in ifBoolean operation in if
7.elif demoelif demo
8.if with elseif with else
9.If statement: a dictionary-based 'switch'If statement: a dictionary-based 'switch'
java2s.com  | Contact Us | Privacy Policy
Copyright 2009 - 12 Demo Source and Support. All rights reserved.
All other trademarks are property of their respective owners.