std::fill_n
From cppreference.com
| Defined in header <algorithm>
|
||
| template< class OutputIt, class Size, class T > void fill_n( OutputIt first, Size count, const T& value ); |
(until C++11) | |
| template< class OutputIt, class Size, class T > OutputIt fill_n( OutputIt first, Size count, const T& value ); |
(since C++11) | |
Assigns the given value value to the first count elements in the range beginning at first if count > 0. Does nothing otherwise.
Contents |
[edit] Parameters
| first | - | the beginning of the range of elements to modify |
| count | - | number of elements to modify |
| value | - | the value to be assigned |
| Type requirements | ||
-OutputIt must meet the requirements of OutputIterator.
| ||
[edit] Return value
| (none) | (until C++11) |
Iterator one past the last element assigned if count > 0, first otherwise.
|
(since C++11) |
[edit] Complexity
Exactly count assignments, for count > 0.
[edit] Possible implementation
template<class OutputIt, class Size, class T> OutputIt fill_n(OutputIt first, Size count, const T& value) { for (Size i = 0; i < count; i++) { *first++ = value; } return first; } |
[edit] Example
The following code uses fill_n() to assign -1 to the first half of a vector of integers:
Run this code
#include <algorithm> #include <vector> #include <iostream> #include <iterator> int main() { std::vector<int> v1{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; std::fill_n(v1.begin(), 5, -1); std::copy(begin(v1), end(v1), std::ostream_iterator<int>(std::cout, " ")); std::cout << "\n"; }
Output:
-1 -1 -1 -1 -1 5 6 7 8 9
[edit] See also
| assigns a range of elements a certain value (function template) | |