C++ program to calculate a to the power b without using power function

Write a C++ program to calculate a to the power b without using power function.

#include<iostream.h>
#include<conio.h>
void main()
{
	int a,b,i,temp=1;
	clrscr();
	cout<<"Enter number for operation";
	cin>>a>>b;
	for(i=1;i<=b;i++)
	{
		temp=temp*a;
	}
	cout<<endl<<"Result are:: "<<temp;
	getch();
}

Ranjith

Site Admin

11 Responses to “C++ program to calculate a to the power b without using power function”

dynamoblaze June 25, 2011

Sir, this gives a^b+1
Reply
swati parmar June 6, 2012

#include
#include
void main()
{
int n,i,c;
clrscr();
printf(“\nEnter a number: “);
scanf(“%d”,&n);
for(i=1;i<=n ;i++)
{
c=n*n;
}
printf("\npower of a number is: %d",c);
getch();
}
Reply
Rahul June 19, 2012

#include
#include

class power
{
int base,exp,i,temp;
public:
void get();
void cal();
void dis();
power()
{
temp=1;
}
};

void power::get()
{
cout<>base>>exp;
}
void power::cal()
{
for(i=1;i<=exp;i++)
{
temp=temp*base;
}
}
void power::dis()
{
cout<<"Calculated="<<temp;
}
void main()
{
clrscr();
power p;
p.get();
p.cal();
p.dis();
getch();
}
Reply
Mani October 11, 2012

Above program gives wrong answers as well as they occupy high memory any more time to type the simple program is
# include
void main()
{
int a;
cout<>a;
cout<<"\n power of "<<a<<" is "<<a*a;
}
Reply
Mani October 11, 2012

SORRY GUYS I MISTAKED IN ABOVE PROGRAM THE CORRECT CODE IS HERE
#include
void main()
{
int a;
cin>>a;
cout<<"\n power of "<<a<<" is
"<<a*a;
}
Reply
aarthy ravichandran February 16, 2013

thanks
Reply
Priyam Gaurav March 5, 2013

This problem can be solved by applying different methods.
1st Method:

#include
#include
void main()
{
int a,b,c,i;
clrscr;
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
c=a;
for(i=1;i<b;i++)
{
c=c*a;
}
printf("Result = %d",c);
getch();
}

2nd Method:

#include
#include
void power(int a, int b);
void main()
{
int a,b;
clrscr();
printf(“Enter the base: “);
scanf(“%d”,&a);
printf(“Enter the power: “);
scanf(“%d”,&b);
power(a,b);
getch();
}
void power(int a, int b)
{
int c;
c=a;
for(i=1;i<b;i++)
{
c=c*a;
}
printf("Result = %d",c);
}

There are so many different methods to solve this problem.
Reply
bilal September 29, 2014

#include
#include

int main ()
{
int a,b,i,temp=1;

printf (“enter value :”);
scanf (“%d”,&a);
printf ( “enter power value :”);
scanf (“%d”,&b);
for (i=1;i<=b;i++)
{
temp= a*temp;
}
printf("vlaue is :%d", temp);

getch();
return 0;
}
Reply
bilal iplanetz.com 03335106003 September 29, 2014

this is easiest one take copy pencil insert value in loop and see how ezily it will
Reply
AB December 5, 2014

Thanx Guys.
U r doing great.
Reply
navin kumar March 1, 2015

how to find power of number without using pow function and multiplication operator ?
Reply