std::count, std::count_if
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                    |  | This page has been machine-translated from the English version of the wiki using Google Translate. 
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| Defined in header <algorithm>
  | ||
| template< class InputIt, class T > typename iterator_traits<InputIt>::difference_type | (1) | |
| template< class InputIt, class UnaryPredicate > typename iterator_traits<InputIt>::difference_type | (2) | |
Retorna o número de elementos no intervalo 
[first, last) satisfazer critérios específicos. A primeira versão conta os elementos que são iguais para value, a segunda versão conta com elementos para os quais predicado p retornos true. Original:
Returns the number of elements in the range 
[first, last) satisfying specific criteria. The first version counts the elements that are equal to value, the second version counts elements for which predicate p returns true. The text has been machine-translated via Google Translate.
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| Índice | 
[editar] Parâmetros
| first, last | - |  a gama de elementos para examinar Original:  the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | 
| value | - |  o valor a ser procurado Original:  the value to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | 
| p | - | unary predicate which returns true  para os elementos necessários . Original:  for the required elements  The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. | 
| Type requirements | ||
| - InputItmust meet the requirements ofInputIterator. | ||
[editar] Valor de retorno
número de elementos que satisfaz a condição.
Original:
number of elements satisfying the condition.
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[editar] Complexidade
exatamente 
last - first comparações / aplicações do predicadoOriginal:
exactly 
last - first comparisons / applications of the predicateThe text has been machine-translated via Google Translate.
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[editar] Possível implementação
| First version | 
|---|
| template<class InputIt, class T> typename iterator_traits<InputIt>::difference_type count(InputIt first, InputIt last, const T& value) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (*first == value) { ret++; } } return ret; } | 
| Second version | 
| template<class InputIt, class UnaryPredicate> typename iterator_traits<InputIt>::difference_type count_if(InputIt first, InputIt last, UnaryPredicate p) { typename iterator_traits<InputIt>::difference_type ret = 0; for (; first != last; ++first) { if (p(*first)) { ret++; } } return ret; } | 
[editar] Exemplo
 O código a seguir usa 
count para determinar quantos números inteiros em uma std::vector corresponder a um valor alvo .
 Original:
 The following code uses 
count to determine how many integers in a std::vector match a target value.
 The text has been machine-translated via Google Translate.
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#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int target1 = 3; int target2 = 5; int num_items1 = std::count(v.begin(), v.end(), target1); int num_items2 = std::count(v.begin(), v.end(), target2); std::cout << "number: " << target1 << " count: " << num_items1 << '\n'; std::cout << "number: " << target2 << " count: " << num_items2 << '\n'; }
Output:
number: 3 count: 2 number: 5 count: 0
 Este exemplo usa um lambda expressão contar elementos divisível por 3 .
 
Original:
 This example uses a lambda expressão to count elements divisible by 3.
 
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#include <algorithm> #include <iostream> #include <vector> int main() { int data[] = { 1, 2, 3, 4, 4, 3, 7, 8, 9, 10 }; std::vector<int> v(data, data+10); int num_items1 = std::count_if(v.begin(), v.end(), [](int i) {return i % 3 == 0;}); std::cout << "number divisible by three: " << num_items1 << '\n'; }
Output:
number divisible by three: 3


