std::is_partitioned
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| Defined in header <algorithm>
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| template< class InputIt, class UnaryPredicate > bool is_partitioned( InputIt first, InputIt last, UnaryPredicate p ); |
(depuis C++11) | |
Retours true si tous les éléments de la gamme
[first, last) qui satisfont le prédicat p présenter à tous des éléments qui n'en ont pas. Renvoie également true si [first, last) est vide .Original:
Returns true if all elements in the range
[first, last) that satisfy the predicate p appear before all elements that don't. Also returns true if [first, last) is empty.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Sommaire |
[modifier] Paramètres
| first, last | - | la plage d'éléments à vérifier
Original: the range of elements to check The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | unary predicate which returns true pour les éléments de se trouver dans le début de la plage . Original: for the elements expected to be found in the beginning of the range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
| Type requirements | ||
-InputIt must meet the requirements of InputIterator.
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[modifier] Retourne la valeur
true si le
[first, last) plage est vide ou est partitionné par p. false autrement .Original:
true if the range
[first, last) is empty or is partitioned by p. false otherwise.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[modifier] Complexité
À la plupart des applications
std::distance(first, last) de p .Original:
At most
std::distance(first, last) applications of p.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
[modifier] Mise en œuvre possible
template< class InputIt, class UnaryPredicate > bool is_partitioned(InputIt first, InputIt last, UnaryPredicate p) { for (; first != last; ++first) if (!p(*first)) break; for (; first != last; ++first) if (p(*first)) return false; return true; } |
[modifier] Exemple
#include <algorithm> #include <array> #include <iostream> int main() { std::array<int, 9> v = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; auto is_even = [](int i){ return i % 2 == 0; }; std::cout.setf(std::ios_base::boolalpha); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::partition(v.begin(), v.end(), is_even); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::reverse(v.begin(), v.end()); std::cout << std::is_partitioned(v.begin(), v.end(), is_even); }
Résultat :
false true false
[modifier] Voir aussi
| divise une série d'éléments en deux groupes Original: divides a range of elements into two groups The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) | |
| (C++11) |
Pour localiser le point de partage d'une gamme partitionné Original: locates the partition point of a partitioned range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (fonction générique) |
