Having with aggregate function
SQL>
SQL>
SQL> CREATE TABLE employees
2 ( employee_id number(10) not null,
3 last_name varchar2(50) not null,
4 email varchar2(30),
5 hire_date date,
6 job_id varchar2(30),
7 department_id number(10),
8 salary number(6),
9 manager_id number(6)
10 );
Table created.
SQL>
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary,department_id ,manager_id)
2 values ( 1001, 'Lawson', '[email protected]', '01-JAN-2002','MGR', 30000,1 ,1004);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id ,manager_id)
2 values ( 1002, 'Wells', '[email protected]', '01-JAN-2002', 'DBA', 20000,2, 1005 );
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id ,manager_id)
2 values( 1003, 'Bliss', '[email protected]', '01-JAN-2002', 'PROG', 24000,3 ,1004);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id, manager_id)
2 values( 1004, 'Kyte', '[email protected]', SYSDATE-3650, 'MGR',25000 ,4, 1005);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id, manager_id)
2 values( 1005, 'Dillon', 'sdillon@a .com', SYSDATE, 'PROG', 20000, 1, 1006);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id,manager_id)
2 values( 1006, 'Beck', '[email protected]', SYSDATE, 'PROG', 20000, 2, null);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id, manager_id)
2 values( 1007, 'Java', '[email protected]', SYSDATE, 'PROG', 20000, 3, 1006);
1 row created.
SQL>
SQL> insert into employees( employee_id, last_name, email, hire_date, job_id, salary, department_id, manager_id)
2 values( 1008, 'Oracle', '[email protected]', SYSDATE, 'DBA', 20000, 4, 1006);
1 row created.
SQL>
SQL> select * from employees;
EMPLOYEE_ID LAST_NAME EMAIL HIRE_DATE JOB_ID DEPARTMENT_ID SALARY MANAGER_ID
----------- -------------------------------------------------- ------------------------------ --------- ------------------------------ ------------- ---------- ----------
1001 Lawson [email protected] 01-JAN-02 MGR 1 30000 1004
1002 Wells [email protected] 01-JAN-02 DBA 2 20000 1005
1003 Bliss [email protected] 01-JAN-02 PROG 3 24000 1004
1004 Kyte [email protected] 13-JUN-98 MGR 4 25000 1005
1005 Dillon sdillon@a .com 10-JUN-08 PROG 1 20000 1006
1006 Beck [email protected] 10-JUN-08 PROG 2 20000
1007 Java [email protected] 10-JUN-08 PROG 3 20000 1006
EMPLOYEE_ID LAST_NAME EMAIL HIRE_DATE JOB_ID DEPARTMENT_ID SALARY MANAGER_ID
----------- -------------------------------------------------- ------------------------------ --------- ------------------------------ ------------- ---------- ----------
1008 Oracle [email protected] 10-JUN-08 DBA 4 20000 1006
8 rows selected.
SQL>
SQL>
SQL> select job_id, avg(salary) avg_salary
2 from employees
3 group by job_id
4 having avg(salary) >= 10000
5 order by avg(salary) desc
6 /
JOB_ID AVG_SALARY
------------------------------ ----------
MGR 27500
PROG 21000
DBA 20000
3 rows selected.
SQL>
SQL> drop table employees;
Table dropped.
SQL>
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