std::swap_ranges
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                    | Defined in header  <algorithm> | ||
| template< class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2 ); | (1) | |
| template< class ExecutionPolicy, class ForwardIt1, class ForwardIt2 > ForwardIt2 swap_ranges( ExecutionPolicy&& policy, ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2 ); | (2) | (since C++17) | 
1) Exchanges elements between range 
[first1, last1) and another range starting at first2. 2) Same as (1), but executed according to 
policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true| Contents | 
[edit] Parameters
| first1, last1 | - | the first range of elements to swap | 
| first2 | - | beginning of the second range of elements to swap | 
| policy | - | the execution policy to use. See execution policy for details. | 
| Type requirements | ||
| - ForwardIt1, ForwardIt2must meet the requirements ofForwardIterator. | ||
| -The types of dereferenced ForwardIt1andForwardIt2must meet the requirements ofSwappable | ||
[edit] Return value
Iterator to the element past the last element exchanged in the range beginning with first2.
[edit] Exceptions
The overload with a template parameter named ExecutionPolicy reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception, std::terminate is called.
- If the algorithm fails to allocate memory, std::bad_alloc is thrown.
[edit] Possible implementation
| template<class ForwardIt1, class ForwardIt2> ForwardIt2 swap_ranges(ForwardIt1 first1, ForwardIt1 last1, ForwardIt2 first2) { while (first1 != last1) { std::iter_swap(first1++, first2++); } return first2; } | 
[edit] Example
Demonstrates swapping of subranges from different containers
Run this code
#include <algorithm> #include <list> #include <vector> #include <iostream> int main() { std::vector<int> v = {1, 2, 3, 4, 5}; std::list<int> l = {-1, -2, -3, -4, -5}; std::swap_ranges(v.begin(), v.begin()+3, l.begin()); for(int n : v) std::cout << n << ' '; std::cout << '\n'; for(int n : l) std::cout << n << ' '; std::cout << '\n'; }
Output:
-1 -2 -3 4 5 1 2 3 -4 -5
[edit] Complexity
linear in the distance between first and last
[edit] See also
| swaps the elements pointed to by two iterators (function template) | |
| swaps the values of two objects (function template) | |
| (parallelism TS) | parallelized version of std::swap_ranges(function template) | 


