std::reverse

 

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is_execution_policy	execution::seqexecution::parexecution::par_unseq	execution::sequenced_policyexecution::parallel_policyexecution::parallel_unsequenced_policy
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all_ofany_ofnone_of (C++11)(C++11)(C++11) for_each for_each_n (C++17)	countcount_if mismatch equal adjacent_find	findfind_iffind_if_not (C++11) find_end find_first_of	search search_n lexicographical_compare lexicographical_compare_3way (C++20)
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C library
qsort	bsearch

 

Defined in header <algorithm>
template< class BidirIt > void reverse( BidirIt first, BidirIt last );	(1)
template< class ExecutionPolicy, class BidirIt > void reverse( ExecutionPolicy&& policy, BidirIt first, BidirIt last );	(2)	(since C++17)

1) Reverses the order of the elements in the range [first, last)

Behaves as if applying std::iter_swap to every pair of iterators first+i, (last-i) - 1 for each non-negative i < (last-first)/2

2) Same as (1), but executed according to policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true

Parameters

first, last	-	the range of elements to reverse
policy	-	the execution policy to use. See execution policy for details.
Type requirements
- BidirIt must meet the requirements of ValueSwappable and BidirectionalIterator.

Return value

(none)

Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

• If execution of a function invoked as part of the algorithm throws an exception and ExecutionPolicy is one of the three standard policies, std::terminate is called. For any other ExecutionPolicy, the behavior is implementation-defined.
• If the algorithm fails to allocate memory, std::bad_alloc is thrown.

Possible implementation

template<class BidirIt> void reverse(BidirIt first, BidirIt last) { while ((first != last) && (first != --last)) { std::iter_swap(first++, last); } }

Example

Run this code

#include <vector>
#include <iostream>
#include <iterator>
#include <algorithm>
 
int main()
{
    std::vector<int> v{1,2,3};
    std::reverse(std::begin(v), std::end(v));
    for(auto e : v) std::cout << e;
    std::cout << '\n';
 
    int a[] = {4, 5, 6, 7};
    std::reverse(std::begin(a), std::end(a));
    for(auto e : a) std::cout << e;
}

Output:

321
7654

Complexity

linear in the distance between first and last

See also

reverse_copy

creates a copy of a range that is reversed (function template)