std::reverse_copy
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header  <algorithm>
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| (1) | ||
|   template< class BidirIt, class OutputIt > OutputIt reverse_copy( BidirIt first, BidirIt last, OutputIt d_first );  | 
(until C++20) | |
|   template< class BidirIt, class OutputIt > constexpr OutputIt reverse_copy( BidirIt first, BidirIt last, OutputIt d_first );  | 
(since C++20) | |
|   template< class ExecutionPolicy, class BidirIt, class ForwardIt > ForwardIt reverse_copy( ExecutionPolicy&& policy,  | 
(2) | (since C++17) | 
1) Copies the elements from the range 
[first, last) to another range beginning at d_first in such a way that the elements in the new range are in reverse order.  Behaves as if by executing the assignment *(d_first + (last - first) - 1 - i) = *(first + i) once for each non-negative 
i < (last - first). If the source and destination ranges (that is, 
[first, last) and [d_first, d_first+(last-first)) respectively) overlap, the behavior is undefined.2) Same as (1), but executed according to 
policy. This overload does not participate in overload resolution unless  std::is_execution_policy_v<std::decay_t<ExecutionPolicy>>  (until C++20)  std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>>  (since C++20) is true.Contents | 
[edit] Parameters
| first, last | - | the range of elements to copy | 
| d_first | - | the beginning of the destination range | 
| Type requirements | ||
 -BidirIt must meet the requirements of LegacyBidirectionalIterator.
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 -OutputIt must meet the requirements of LegacyOutputIterator.
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 -ForwardIt must meet the requirements of LegacyForwardIterator.
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[edit] Return value
Output iterator to the element past the last element copied.
[edit] Complexity
Exactly last - first assignments.
[edit] Exceptions
The overload with a template parameter named ExecutionPolicy reports errors as follows:
-  If execution of a function invoked as part of the algorithm throws an exception and 
ExecutionPolicyis one of the standard policies, std::terminate is called. For any otherExecutionPolicy, the behavior is implementation-defined. - If the algorithm fails to allocate memory, std::bad_alloc is thrown.
 
[edit] Notes
Implementations (e.g. MSVC STL) may enable vectorization when the both iterator types satisfy LegacyContiguousIterator and have the same value type, and the value type is TriviallyCopyable.
[edit] Possible implementation
See also the implementations in libstdc++, libc++, and MSVC STL.
template<class BidirIt, class OutputIt> constexpr // since C++20 OutputIt reverse_copy(BidirIt first, BidirIt last, OutputIt d_first) { while (first != last) { *(d_first++) = *(--last); } return d_first; }  | 
[edit] Example
Run this code
#include <vector> #include <iostream> #include <algorithm> int main() { auto print = [](std::vector<int> const& v) { for (const auto& value : v) std::cout << value << ' '; std::cout << '\t'; }; std::vector<int> v({1,2,3}); print(v); std::vector<int> destination(3); std::reverse_copy(std::begin(v), std::end(v), std::begin(destination)); print(destination); std::reverse_copy(std::rbegin(v), std::rend(v), std::begin(destination)); print(destination); }
Output:
1 2 3 3 2 1 1 2 3
[edit] See also
|    reverses the order of elements in a range   (function template)  | |
|    (C++20)  | 
   creates a copy of a range that is reversed   (niebloid)  |